You can buy 'load equalizers' for this, although they're pretty pricey. All you need is a 6 ohm resistor in parallel with each LED replacement (a 3 ohm if you replace f/r, a 2.5 ohm if you do both and the indicator). I don't know if you could just put this in line with the flasher, or if you'd have to do each side by itself because of the canceller unit.
And before you rush off to radio shack, bear in mind these can get hot, so don't use one rated for less than 25 watts, 50 watts would be much better, with a 100 watt unit being bullerprooof. These will be dissapating the equivilent wattage as heat, so a 25 watt 6 ohm resistor for a 27 watt load will be operating above 100%. Also don't install it where it could melt anything in contact with it...
But if you're doing this to 'save power', don't; you'll be using the same amount, just in a different way. To save amps, you'll have to give up the self-cancel feature.
And before you rush off to radio shack, bear in mind these can get hot, so don't use one rated for less than 25 watts, 50 watts would be much better, with a 100 watt unit being bullerprooof. These will be dissapating the equivilent wattage as heat, so a 25 watt 6 ohm resistor for a 27 watt load will be operating above 100%. Also don't install it where it could melt anything in contact with it...
But if you're doing this to 'save power', don't; you'll be using the same amount, just in a different way. To save amps, you'll have to give up the self-cancel feature.
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